Feeling lost in the world of random DSA topics, wasting time without progress? It's time. In each step, the fire will burn its side-adjacent cells and the person will move from. G-13. edge [i] contains the cell number that can be reached from of cell ‘i’ in one step. Priority queue of pairs in C++ (Ordered by first) Count all elements in the array which appears at least K times after their first occurrence. Distance matrix: stores the distance of the nearest cell having 1 for every particular cell. Given an integer target which represents the total distance to be covered by a car on a straight road. Iterate through each cell of the matrix, let the current cell be (i, j) where i is the row index and j is the column index. We can get above formula by simply applying Pythagoras theorem. Replace every element with the next greatest element (greatest element on its right side) in the array. To calculate the cost (i) using Dynamic Programming, we need to have some recursive relation in terms of sub-problems. Expected Time Complexity: O (m* log (n)) Expected Space Complexity: O (n) Constraint: 2 <= n <= 105. Select D’ ⊆ D, the set of k nearest training data points to the query points; Predict the class of the query point, using distance-weighted voting. Follow the given steps to solve the problem: This video explains the problem efficiently by using only O (N*M) Space Complexity and O (N*M) Time Complexity to traverse through the Matrix . The distance is calculated as |i1 – i2| + |j1 – j2|, where i1, j1 are the row number and column number of the current cell and i2, j2 are the row number and column number of the nearest cell having value 1. Initialize a priority queue to store the cells to be processed, and add the source cell to the priority queue. Paytm. 5) Create an array strip[] that stores all points which are at most d distance away from the middle line dividing the two sets. GfG Weekly + You = Perfect Sunday Evenings! Given an array with repeated elements, the task is to find the maximum distance between two occurrences of an element. a) Find mid = (l+r) / 2 b) Find sum from 1 to mid using formula mid* (mid+1)/2 c) If sum of mid natural numbers is equal to n, return mid. Find the distance of. Minimum distance to the corner of a grid from source; Distance of nearest cell having 1 in a binary matrix; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell; Implementing Water Supply Problem using Breadth First Search; Shortest path between two points in a Matrix with at most K obstaclesQuick Link0:00 Introduction. Example 1: Given a matrix mat of size N x M where every element is either 'O' or 'X'. Distance of nearest cell having 1 in a binary matrix; Sum of all parts of a square Matrix divided by its diagonals; Check if the structure is stable or not after following given conditions; Minimum cells traversed to reach corner where every cell represents jumps; Construct a Matrix of size NxN with values in range [1, N^2] as per given conditionsA Computer Science portal for geeks. If there is no cycle in the graph then return -1. Try all 8 possible positions where a Knight can reach from its position. The distance is calculated as |i 1 - i 2 | + |j 1 - j 2 |, where i 1, j 1 are the row number and column number of the current cell, and i 2, j 2 are the row number and column number of the nearest cell having value 1. For assigning the maximum priority. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. so the total number of Node is N * N. Mark the source cell as visited and initialize its distance to 0. 1. ; Loop till queue is empty. If n = 1, then it should return 1. If there are no negative weight cycles, then we can solve in O (E + VLogV) time using. For each tower, you must perform exactly one of the following operations exactly once. The distance is calculated as |i1 - i2| + |j1 - j2|, where i1, j1 are the row number and column number of the current cell, and i2, j2& Find the distance of the nearest 1 in the grid for each cell. For instance, if you want to prepare for a Google interview, we have an SDE sheet specifically designed for that purpose. Recommended: Please try your approach on {IDE} first, before moving on to the solution. If the element is found, return its index. The K-Nearest Neighbor (KNN) algorithm is a popular machine learning technique used for classification and regression tasks. The distance between two adjacent cells is 1. cpp. Euclidean distance of (1, 3) and (2, 3) = &root;((1 – 2) 2 + (3 – 3) 2) = 1. Array may contain duplicate values. Contests. It relies on the idea that similar data points tend to have similar labels or values. The cells are named with an integer from 0 to N-1. The idea is, sum of S1 is j and it should be closest. 0:57 Example Explanation. Solutions (2. You must do it in place. Re-insert val+1 and their indexes of all the valid moves to the queue. 3- Return -1, if not possible. Nearest 1 in a binary matrix; Distance of nearest cell having 1 in a binary matrix; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell; Word Ladder - Set 2 ( Bi-directional BFS ) Minimum distance to the corner of a grid from source Below are the steps involved in the implementation of the code: Initializes an array res of length n with -1, where n is the length of the input array arr. Determine whether or not there exist two elements in Arr whose sum is exactly X. Input : s = 20, d = 3 Output : 299. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"2D Hopscotch. Edit Distance Using Dynamic Programming (Bottom-Up Approach): . e. Space Complexity: O(n). Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's. Do all the possible moves (right, left, up and down) possible. The distance is calculated as |i1 – i2| + |j1 – j2|, where i1, j1 are the row number and column number of the current cell and i2, j2 are the row number and column number of the nearest cell having value 1. cpp. The only problem is I am able to do it with two dfs but I was told to do it in O (logn). The new groups that can be formed by considering a member of every group are (1, 4), (2, 4), (3, 4). Dist (n1, n2) = Dist (root, n1) + Dist (root, n2) - 2*Dist (root, lca) 'n1' and 'n2' are the two. First find all islands in the Grid using DFS. GfG-Problem Link:. Iterate until you don't need any update. You can travel back in time within the same calendar year. Elements greater than the previous and next element in an Array. e. The second line has a list of N values of the edge [ ] array, where edge [i] conatins the cell. Show topic tag. The v represents the class labels. You are given the tree in the form of an array A[1. Given a 2D Array/Matrix, the task is to find the Peak element. Every cell of the maze contains these numbers 1, 2 or 3. . It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. cpp. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Following is the formula. github","contentType":"directory"},{"name":"javascript clock","path. Explanation: Largest minimum distance = 5. It also help to crack the technical inteviews. Constraints :K-NN is less sensitive to outliers compared to other algorithms. Visited array: an array initialized to 0 indicating unvisited nodes. To count number of groups, we need to simply count. Input: arr [] = {2, 5, 3, 5, 4, 4, 2, 3}, x = 3, y = 2. The Nth Fibonacci Number can be found using the recurrence relation shown above: if n = 0, then return 0. The next greater element for 71 is 72, which is at position 5. Distance =. Given a grid of size n*m (n is the number of rows and m is the number of columns in the grid) consisting of '0's (Water) and '1's(Land). 3) Recursively find the smallest distances in both subarrays. Replace all 'O' or a group of 'O' with 'X' that are surrounded by 'X'. Your task is to complete the function FindWays () which takes matrix as input parameter and returns a list containg total number of ways to reach at (n, n) modulo 109 + 7 and maximum number of Adventure. cpp. If the element is the leftmost element, nearest smaller element on left side is considered as 0. Compute d(x i, x) for i = 1, . Count of cells in a matrix which give a Fibonacci number when the. Quick Link 0:00 Introduction. In each step, write value of distance to the answer array. Find out the minimum steps a Knight will take to reach the target position. Traverse through the array starting from the first element. Algorithm. d) Else if sum > n, r = mid - 1. Initialize a priority queue to store the cells to be processed, and add the source cell to the priority queue. Product Based Company SDE Sheets. Link: Link: Sum of minimum and maximum elements of. , the memory location of the first element of the array (generally denoted by the name of the array). If the x and y become the boundary edges any time return val. + 3 more. github","path":". Given an array of size N consisting of only 0's and 1's. 26th April. Find the distance of the nearest 1 in the grid for each cell. 0:57 Example Explanation. Find the closest pair from two sorted arrays. Solve company interview questions and improve your coding intellect{"payload":{"allShortcutsEnabled":false,"fileTree":{"Graph/Geeksforgeeks":{"items":[{"name":"Alex Travelling using Bellman Ford. . Note: The cells are named. s represents ‘source’. Element with left side smaller and right side greater. The largest possible difference will be a[n-1] - a[0] after sorting the array. Find the distance of the nearest 1 in the grid for each cell. Distance of nearest cell having 1 in a binary matrix; Sum of all parts of a square Matrix divided by its diagonals; Check if the structure is stable or not after following given conditions; Minimum cells traversed to reach corner where every cell represents jumps; Construct a Matrix of size NxN with values in range [1, N^2] as per given conditionsPractice. A tag already exists with the provided branch name. The nearest perfect square of arr [3] (= 13) is 16. If it contains 1 : means we can go Right from that cell only. where, diffOfX = difference between knight’s x-coordinate and target’s x-coordinate. Back to Explore Page. To find Minimum sum difference, we have to find j such. This makes it easier to calculate the position of each element by simply adding an offset to a base value, i. Find the distance of the nearest 1 in the grid for each cell. Proposition: The function d is a metric. Description. Menu. Example 1: Input: matrix [] [] = { {1, 0},3. Below is the implementation of above idea. , in all 8 directions. You don't need to read or print anything, Your task is to complete the function nearest () which takes the grid as an input parameter and returns a matrix of the same dimensions. Enqueue the cells with 1 value in the queue with the distance as. 3 elements arranged at positions 1, 7 and 12, resulting in a minimum distance of 5 (between 7 and 12) A Naive Solution is to consider all subsets of size 3 and find the minimum distance for every subset. We have discussed a DFS based solution to detect cycle in a directed graph. Explanation: Largest minimum distance = 5. Key Pair. that Min {sum - 2*j : dp [n] [j] == 1 } where j varies from 0 to sum/2. The idea is to calculate the Euclidean distance from the target for every given point and store them in an array. {"payload":{"allShortcutsEnabled":false,"fileTree":{"Graph/Geeksforgeeks":{"items":[{"name":"Alex Travelling using Bellman Ford. Solve Problems. If it has less, we add the item to it regardless of the distance (as we need to fill the list up to k before we start rejecting items). #stacks #queues #stackqueue #competitiveprogramming #coding #dsa Hey, Guys in this video I have explained how we can solve the problem 'Distance of nearest c. Raw Blame. Time Complexity: O(n) Auxiliary Space: O(1) Method 2 (Binary Search) First check whether middle element is Fixed Point or not. You have to find: Nearest meeting cell: Given any two cells - C1, C2, find the closest cell Cm that can be reached from both C1 and C2. The distance is calculated as |i 1 - i 2 | + |j 1 - j 2 |, where i 1, j 1 are the row number and column number of the current cell, and i 2, j 2 are the row number and column number of. 77, which is minimum obtainable total distance. Step3: Initialize the start index with level = 0 and reduce the matrix. Distance of nearest cell having 1 in a binary matrix; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell; Implementing Water Supply Problem using Breadth First Search; Shortest path between two points in a Matrix with at most K obstacles; Minimum distance to fetch water from well in a village Quick Link0:00 Introduction. We can get above formula by simply applying Pythagoras theorem. Find the distance of the nearest 1 in the grid for each cell. There should be atleast one 1 in the grid. The smallest of them is 18. Initialize a counter [] [] vector, this array will keep track of the number of remaining obstacles that can be eliminated for each visited cell. Step 2 − Next, we need to choose the value of K i. Equal Sum. Expected Auxiliary Space is O (MN) for a M x N matrix. Distance of nearest cell having 1 | 0/1 Matrix | C++ | Java. There are n stairs, and a person is allowed to jump next stair, skip one stair or skip two stairs. Ln 1, Col 1. Implementation of Efficient Approach: C++ // C++ program to demonstrate // multi-source BFS. Check if n2 or any of its. 0:09 Understanding Problem. An Efficient Solution is based on Binary Search. You are given a weighted undirected graph having n vertices numbered from 1 to n and m edges describing there are edges between a to b with some weight, find the shortest path between the vertex 1 and the vertex n and if path does not. Hiring Challenge for Working Professionals on 10th November. The distance between two adjacent cells is 1. Therefore, the following relation gives the sum of distances of all nodes from a node,. The idea is to modify the given matrix, and perform DFS to find the total number of islands. cpp","contentType":"file"},{"name":"3 Divisors. e, zero points. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. Euclidean distance is the most common distance measure in scientific applications of the Voronoi diagram. Note: If the Graph contains a negative cycle then return an array consisting of only -1. Source is already a corner of the grid. Find the minimum numb. Find k distant string of given string. Get the front element (x, y, val = moves) in the queue and mark vis [x] [y] as visited. Path is:: 2 1 0 3 4 6. Finding LCA becomes easy when parent pointer is given as we can easily find all ancestors of a node using parent pointer. Approach: The dynamic programming approach is preferred over the general recursion approach. If a vertices can't be reach from the S then mark the distance as 10^8. You can possibly make zero operations to get. Then minimum steps will be 4. The distance between two adjacent cells is 1. You have got a maze, which is a n*n Grid. Follow the steps below to implement the idea: Create two variables, l and r, initialize l = 0 and r = n-1. Does robot moves circular. The distance is calculated as|i1- i2| + |j1- j2|, where i, jare the row number and column number of the current cell,. Solve DSA problems on GfG Practice. Easy 224K 27. Given an array Arr of N positive integers and another number X. It is not dependent on the actual values of xi and yi but only if they are equal to each other or not equal. Now sort it to find minimum middle position, which will be the best meeting point. 542. The new groups that can be formed by considering a member of every group are (1, 4), (2, 4), (3, 4). Distance measures. C++ Program for Shortest distance between two cells in a matrix or grid. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":". Use a stack pre to find the index of the nearest smaller tower to the left of the current tower. cpp. 0:57 Example Explanation. Input: N = 4, arr = {2, 4, 8, 0} Output: 4 Explanation: Among possible rotations of given array, the rotations 8 0 2 4 and 0 2 4 8, have the maximum hamming distance of 4. A Computer Science portal for geeks. This is the best place to expand your knowledge and get prepared for your next interview. Practice. Set value of count [i] [0] equal to 1 for 0 <= i < M as the answer of subproblem with a single column is equal to 1. Apply to 6 Companies through 1 Contest! Given an array arr [] denoting heights of N towers and a positive integer K. There should be atleast one 1 in the grid. That is to say, if you. If the link list does not have any loop, X=0. Check if set of first X elements of one Array is same as set of first Y elements of other. There is only one cell so cell 0 has maximum weight. cpp","path":"Graph/Geeksforgeeks/Alex. The task is to find the closest value to the given number in array. The graph is represented as an adjacency matrix of size n*n. You can use a maximum of 3 time machines in a month. Check if a path exists for a cell valued 1 to reach the bottom right corner of a Matrix. In this post, BFS based solution is discussed. Feeling lost in the world of random DSA topics, wasting time without progress?. Contests. The task is to find the largest sum of a cycle in the maze (Sum of a cycle is the sum of the cell indexes of all cells present in that cycle). Problems Courses Get Hired; Upcoming. Diameter of a Bianry Tree. Example 2: Input: N = 1500 Output: 1521 21 Explanation: Two of the. Find the distance of the nearest 1 in the grid for each cell. Practice. Q2: How to Find Distance Between Two Points in 2D? Answer: We can find the distance between two points (x 1, y 1) and (x 2, y 2) using the distance formula as follows:Input: Number of people = 4 Relations : 1 - 2 and 2 - 3 Output: Number of existing Groups = 2 Number of new groups that can be formed = 3 Explanation: The existing groups are (1, 2, 3) and (4). Solve Problem. We have discussed different approaches to find LCA in set 1. This auxiliary stack will keep track of the maximum element. This problem can be solved by observing the. . If it contains 2 : means we can go Down from that cell only. Example 1: Input: N = 13 , M = 4 Output: 12 Explana. a = (n / 10) * 10. Find the distance of the nearest 1 in the grid for each cell. Given n integer coordinates. Constraints : K-NN is less sensitive to outliers compared to other algorithms. So Balanced BST-based method will also take O(n log k) time, but the Heap based method. GfG-Problem Link: and Notes Link: Series: 1 in a binary matrix; Distance of nearest cell having 1 in a binary matrix; Minimum distance to the corner of a grid from source; Minimum cost to reach from the top-left to the bottom-right corner of a matrix; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell{"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":". gitattributes","path":". Explanation: 3 is at index 7 and 2 is at index 6, so the distance is 1. Start with a matrix with 0 where the 1 are located and a large number (larger then any possible distance) on the other cells. b) Then throw 6 to reach 28. Input: The first line of input is an integer T denoting the. Input: N = 1, Edge [] = {-1} Output: 0. java","path":"Stack-Queue/Circular_tour. You need to find the the length of the largest cycle in the maze. Formally, select a range (l, r) in the array A [], such that (0 ≤ l ≤ r < n) holds and flip the elements in this range to get the maximum ones in the final array. push all the cells it can visit in the queue. The distance is calculated as |i1 - i2| + |j1 - j2|, where i1, j1 are the row number and column number of the current cell, and i2, j2&. 1. Let us first verify that the conditions of DP are still satisfied. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"1832. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":"0239-sliding-window-maximum","path":"0239-sliding-window-maximum","contentType":"directory. The distance is calculated as |i1 - i2| + |j1 - j2|, where i1, j1 are the row number and column number of the current cell, and i2, j2 are the row number and column number of the nearest cell having value 1. {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":". Time Complexity: O(K) + O(m * log(k)) , where M = N – K Auxiliary Space: O(K) Note: We can also use a Balanced Binary Search Tree instead of a Heap to store k+1 elements. If all squares are visited print the solution Else a) Add one of the next moves to solution vector and recursively check if this move leads to a solution. The entries where j < i are meaningless. , grid [m - 1] [n - 1]). Output: The minimum cost is 65 The minimum cost can be obtained by first going to station 1 from 0. There should be atleast one 1 in the grid. BiWizard School Contest. The distance is calculated as |i1 - i2| + |j1 - j2|, where i1, j1 are the row number and column number of the current cell,. VMWare. Hence, the shortest distance of node 0 is 0 and the shortest distance. cpp. Given a Matrix of size N*N filled with 1 ‘s and 0 ‘s, the task is to find the maximum. Detect loop in a LL. There is only one cell which has maximum weight (i. 1) Sort the given array a[]. We have to determine what is the earliest time after which all the oranges are rotten. Distance of nearest cell having Ask Question Asked 11 months ago Modified 11 months ago Viewed 17 times 0 Given a binary grid of n*m. For each 0-cell, compute its distance from every 1-cell and store the minimum. Find the K closest points to origin using Priority Queue. The K-NN algorithm works by finding the K nearest neighbors to a given data point based on a distance metric, such as Euclidean distance. -1), whose total distance with other points is 20. The distance is calculated as |i1 - i2| + |j1 - j2|, where i1, j1 are the row number and column number of the current cell, and i2, j2 are the row number and column number of the nearest cell having value 1. If no valid path exists then print -1. Nearest 1 in a binary matrix; Distance of nearest cell having 1 in a binary matrix; Minimum distance to the corner of a grid from source; Minimum cost to reach from the top-left to the bottom-right corner of a matrix; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell Distance of nearest cell having 1 in a binary matrix; Minimum cost to reach from the top-left to the bottom-right corner of a matrix; Convert given lower triangular Matrix to 1D array; Minimum number of jumps to obtain an element of opposite parity; Check if cells numbered 1 to K in a grid can be connected after removal of atmost one blocked cell Constraints: 1 ≤ n, m ≤ 500. The K-NN algorithm works by finding the K nearest neighbors to a given data point based on a distance metric, such as Euclidean distance. Check if the Sentence Is Pangram. The idea is to store multiple items of the same type together. Unique Paths II - You are given an m x n integer array grid. Find the vertical distance from P 1 to P 2. You switched accounts on another tab or window. Step2: Do following for every row after the first row. Determine if Two Trees are Identical. Example 1: Input: N = 7, X = 2 Arr[] = {1, 1, 2, 2, 2, 2, 3} Output: 4 Explanation: 2 occurs 4 times in the given array. Firstly, pre-compute the xor of all the elements of each row and column separately. If the x and y become the boundary edges any time return val. So Balanced BST-based method will also take O(n log k) time, but the Heap based method. Ln 1, Col 1. A Diagonal adjacent is not considered a neighbour. weight of 3rd cell = 0. Example 1: Input: E = [[0,1,9]] S = 0 Output: 0 9 Explanation: Shortest distance of all. We can calculate Minkowski distance between a pair of vectors by apply the formula, ( Σ|vector1i – vector2i|p )1/p. Store all horizontal and vertical positions of all group member. Time. This video explains the problem efficiently by using only O (N*M) Space Complexity and O (N*M) Time Complexity to traverse through the Matrix . Count cells in a grid from which maximum number of cells can be reached by K vertical or horizontal jumps. Your task is to complete the function getXor to return the XOR of the given range a and b. Two cells are. Method 1: Recursive. cpp. Find the distance of the nearest 1 in the grid for each cell. After including 0 to sptSet, update distance values of its adjacent vertices. If the popped cell is the destination cell, return its distance. Editorial. Maximum of all distances to the nearest 1 cell from any 0 cell in a Binary matrix. Step1: Create a class (Node) that can store the reduced matrix, cost, current city number, level (number of cities visited so far), and path visited till now. Approach using sorting based on distance: This approach is explained in this article. Given a matrix of dimension m * n where each cell in the matrix can have values 0, 1, or 2 which has the following meaning: . Otherwise, for each of four adjacent cells of the current cell, enqueue each valid cell with +1 distance. Exclusively for Freshers! Participate for Free on 21st November & Fast-Track Your Resume to Top Tech Companies. Reload to refresh your session. While the priority queue is not empty, pop the cell with the minimum distance from the priority queue. The minimum number of jumps to reach end from first can be calculated using the minimum value from the recursive calls. the only used space is dp vector of o(n). An array is a collection of items stored at contiguous memory locations. 2- Apply binary search from l to r. the nearest data points. So the idea is to do a breadth-first search from the starting cell till the ending cell is. There are two types of nodes to be considered. Find the distance of the nearest 1 in the grid for each cell. The insert and delete operations on Balanced BST also take O(log k) time. Distance of Nearest Cell having 1 Problem Statement: Given a binary grid of N*M. The tree contains N nodes, labeled 1 to N. Two cells are. . Input: The first line of input is an integer T denoting the. . Below is the step by step algorithm to do this : Create an auxiliary stack, say ‘trackStack’ to keep the track of maximum element. Example 1: [Input: mat = [[0,0,0],[0,1,0],[0,0,0]] Output: [[0,0,0],[0,1,0],[0,0,0]] Example 2: [Input: mat = [[0,0,0],[0,1,0],[1,1,1]] Output: [[0,0,0],[0,1,0],[1,2,1. Approach: Follow the steps below to solve the problem: Traverse the array from left to right. vscode","path":". Following are simple steps to do this special flood fill. We need to find minimum initial points to reach cell (m-1, n-1) from (0, 0). {"payload":{"allShortcutsEnabled":false,"fileTree":{"":{"items":[{"name":". Count ordered pairs of Array elements such that bitwise AND of K and XOR of the pair is 0. 4) deleteMiddle () which will delete the middle element. For example :Complete the function booleanMatrix () that takes the matrix as input parameter and modifies it in-place. So the idea is to do a breadth-first search from the starting cell till the ending cell is found. Now, BFS can be used to find the shortest path from the cell. Elements in the Range. e 2) So, cell 2 is the output. Find whether there is path between two cells in matrix using Breadth First Search: The idea is to use Breadth-First Search. Medium Accuracy: 15. . 542. We can change all its values to 100 with minimum cost, |1 - 100| + |100 - 100| + |101 - 100| = 100. Sample Output 1 : 5 2 Explanation of Sample Input 1 : For the first test case, the shortest path between the source cell (0, 0) and destination cell (2,3) is highlighted in the figure below, having a length of 5. Examples: Input: N = 15, M = 12, R = 1, C = 6. There should be atleast one 1 in the grid.